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Rated power refers to the power of the normal operation of the appliance. Its value is the rated voltage of the electrical appliance multiplied by the rated current. If the actual power of the appliance is greater than the rated power, the electrical appliance may be damaged, and if the actual power is less than the

Codeforces Round #513 by Barcelona bootcamp (rated, div. 1 + div. 2) Solved:2 out of 8 ... rank:2730 Unrated A. Phone Numbers Difficulty: Universal group. Simulation can be: Summary: Do not waste too much time on simple questions, to improve the accuracy of the problem. #include B. Maximum Sum of Digits Difficulty: Increase group D1T1? greedy for numbers less than 10, a = N, b = 0

=" has been evaluated by the FU network "Excellent enterprise Mailbox Service provider". png "alt=" Wkiol1atf7crvhdwaasnoxnw1l4687.png "/>Fu Network has been rated "excellent enterprise Mailbox service provider"This election and won the prize, the company's general manager of the network cloud hosting industry Center, Mr. Yang Sheng, interviewed by IDC, said that thanks to the network of friends and partners to have the love of the net, inspire the ne

) - { theans+=b[x];x-=lowbit (x); * } $ returnans;Panax Notoginseng } - intMain () the { +scanf" %d%d%d",n,k,d); A for(intI=1; i) the { +scanf"%d",a[i]); - } $Sort (A +1, A +1+n); $Add (n+1); - for(inti=n-k+1; i>=1; i--) - { the intPos=upper_bound (A +1, A +1+N,A[I]+D)-A; - if(pos>=i+k-1Get(POS)-Get(i+k-1) >0)Wuyi { thev[i]=true; Add (i); - } Wu } - if(v[1]) printf ("yes\n"); About Elseprintf"no\n"); $ return 0; -}

$ for(intv=1; v1; v++)//V is the lesson on the first few SectionTo $ { -P[i][j]=min (p[i][j],a[i][v+num[i]-j-1]-a[i][v]+1); - } the } - }Wuyill sum=0; the for(intI=0; i) -sum+=p[i][0]; WuMemset (DP,0,sizeof(DP)); - for(intI=0; i) About //Group Backpack $ for(intj=k;j>=0; j--) - for(intv=0; V) - if(JGT;=V)//not written at first, the array may be out of bounds, written on the ri

it is borrow (0,1), current digital and for nowShould pay attention to the borrow and not borrow the case of the decision (originally to consider less than borrow 9 can not borrow, was hack)1#include 2 using namespacestd;3 intans=0, a[ the]={0};4 intmark[ the][5][255]={0};5 intDfsintIdintBorintNow )6 {7 if(id==a[0]+1)8 {9ans=Max (ans,now);Ten returnans; One } A - if(mark[id][bor][now]!=-1)returnMark[id][bor][now]; - the inttmp=0; - if(a[id]!=0) Tmp=max

#include #include#includestring.h>#include#definell Long Long#defineRep (i,j,k) for (Long long i=j;i#definePer (i,j,k) for (Long long i=j;i>=k;i--)using namespacestd;Const intN = 2e5+5; ll H[n];intMain () {Long Longn,k; while(~SCANF ("%lld%lld",n,k)) {memset (H,0,sizeof(h)); LL Maxx=0; ll X; LL Minn=2e5+5; for(intI=1; i) {scanf ("%lld",x); H[X]++; Minn=min (minn,x); Maxx=Max (maxx,x); } ll sum=0; Per (I,maxx-1, Minn) h[i]=h[i+1]+H[i]; intCnt=0;//cout//Rep (I,minn,maxx) {//printf ("%d", H[

=strlen (A +1); for(intI=1; iTen; i++) { for(intj=1; j) { for(intk=0; k4; k++) { for(intL=j; li)if(ch[k]==A[l]) tree[i][j][k].update (L,1); } } } intQ; scanf ("%d",q); while(q--) { intT; scanf ("%d",t); if(t==1) { intx; Charf[2]; scanf ("%d%s",x,f); if(a[x]==f[0])Continue; for(intI=1; iTen; i++) { for(intj=1; j) { if(x%i==j%i) for(intk=

Https://zh.wikipedia.org/wiki/%E8%BC%BE%E8%BD%89%E7%9B%B8%E9%99%A4%E6%B3%95The same is true of the model, when it is reduced several times.In Euclid's initial description, the quotient and remainder are computed by successive subtraction, that is, the R K −1 is subtracted from the Rk −2 until it is less than Rk− 1. A more efficient approach is to use integer division and modulo to compute quotient and remainder: R k ≡ rk−2 mod rk−1 subtraction version defined in Eucl

As the heart of the computer hardware system, although the power supply does not determine the performance, it determines the stability and durability of performance. Our knowledge of the power supply is wrapped in a metal shell. This also greatly reduced our understanding of the power supply, we need only through the power supply nameplate, Power module composition and so on can see the origin of power and quality. However, although this is not enough, because of artificial misleading and netwo

The user shall select the required UPS Output Power KVA value based on the statistical value of the device load). To ensure the UPS system efficiency and prolong the UPS Service life as much as possible, the recommended parameters are: the user load only accounts for 60% of the UPS output power ~ 70% is recommended. Selection of UPS rated output capacity The user shall select the required UPS Output Power KVA value based on the statistical value of th

The rated energy must not exceed 160Wh, equal to how many mah battery capacity?The action power supply capacity indicator, correct should be marked with WHR (WH) watt hour, but the volume of the advertised power supply is usually used Xx000mahWHr watt Hour, which is the operational power output power unit, P (WHR) =v voltage x I (capacitance AH).The general lithium battery voltage is 3.7V, so 160Whr conversion into electric capacity mah algorithm is 1

, longer lengths, i.e. larger areas After that, you can select another sequence in two, use a double loop to get the sub-columns, and then divide the limit by this sum to get a target value. After that, in the array of initial preprocessing to find the target value, return is greater than its first value, that is, with Upper_bound, to find the length minus one, so that the longest length. Finally, by multiplying the length of the lookup with the length of the current child column, the result is

Star rating of five stars:Description: The hypothesis is to use three kinds of pictures to display star rating, that is 1. Bright Star 2. Half-bright stars 3. Stars that are not bright;The full score is 5 points; (here of course it can be variable as a parameterThe function passed in parameter grade represents the current score. functionStar_show (grade) {varStar = 0,//number of stars litHalf = 0,//half-Bright Star 1 is half the caseNostar = 0;//number of stars not litGrade =parsefloat (grade

A. diverse substring (prefix and) Question: Give a string, find a substring that meets the requirements of each letter in the substring to appear no more than the length of the substring/2, the length of the string n Question: the starting and ending points of the N-party enumerative substrings. Create a prefix for each letter and you will be able to know the number of each letter in any string. Code: #include Educational codeforces round 53 (rated

Topic Links:Http://www.codeforces.com/contest/655/problem/DTest instructionsThe problem is that the first K-sessions are required to determine the unique topological order, and the minimum k to satisfy the condition is obtained.ExercisesThe value of the binary K, do the topological sort as long as only one element at a time without a precursor can be unique.#include #include#include#include#include#includeusing namespacestd;Const intMAXN =101010;intN, M;structEdge {intV, NE; Edge (intVintne): V

); - } About Else $ { - if(p>d)Continue; - Dd.push_back (Make_pair (p,b)); -dd_max=Max (dd_max,b); A } + } the if(cc_max!=0 dd_max!=0) Ans=cc_max+dd_max;//first Case -Ans=max (Ans,solve (cc,c));//Two of them are coins . $Ans=max (Ans,solve (dd,d));//Two of them are diamonds . theprintf"%d\n", ans); the } the return 0; the}In addition, the tree array can also be done, you can refer to http://blog.csdn.net/ssimpl

"Sohu It News" Beijing time October 12 News, Commercial Insider (Business Insider) website recently rated the 20 most innovative technology start-up companies in the United States, now listed as follows:1. Fun Programming Website CodecademyFounder: Zach Sims, Ryan BubinskiLives in New York, NYFinancing amount: $2.5 million, Union Square ventures collar.Why: Codecademy makes learning JavaScript basic knowledge simple and interesting. The first task is

Title Link: Http://codeforces.com/contest/1016/problem/BGive two string s,t, and then give an interval of s, asking how many substrings exist in the substring that are the same as TIf a lookup is timed out, you only need to prefix and subtract#include using namespacestd;intn,m,q;strings,t;intL,r;inthay[10000],shay[10000];intMain () {Ios::sync_with_stdio (false); CIN>>n>>m>>Q; CIN>>s>>T; S=" "+s; T=" "+T; for(intI=1; i1; i++) {Hay[i]=1; for(intj=0; j) { if(s[i+j]!=t[1+J]) {Hay

diamonds.AC Code:1#include 2 #defineINF 0x3f3f3f3f3 #definell Long Long int4 using namespacestd;5 6 Const intMAXN = 1e5+Ten;7 8 intT_1[MAXN], T_2[MAXN];9 intN, Num_c, num_d;Ten One intLowbit (intx) A { - returnx (-x); - } the voidAddintNointStintvalue) - { - for(inti = st; I lowbit (i)) - { + if(no) t_1[i] =Max (T_1[i], value); - ElseT_2[i] =Max (T_2[i], value); + } A } at - intQueryintNointSt) - { - intres =0; - for(inti = st; i >0; i-=lowbit (i)) -